2x^2+4x+8=

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Solution for 2x^2+4x+8= equation:


Simplifying
2x2 + 4x + 8 = 0

Reorder the terms:
8 + 4x + 2x2 = 0

Solving
8 + 4x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + 2x + x2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(4 + 2x + x2)' equal to zero and attempt to solve: Simplifying 4 + 2x + x2 = 0 Solving 4 + 2x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-4' to each side of the equation. 4 + 2x + -4 + x2 = 0 + -4 Reorder the terms: 4 + -4 + 2x + x2 = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 2x + x2 = 0 + -4 2x + x2 = 0 + -4 Combine like terms: 0 + -4 = -4 2x + x2 = -4 The x term is 2x. Take half its coefficient (1). Square it (1) and add it to both sides. Add '1' to each side of the equation. 2x + 1 + x2 = -4 + 1 Reorder the terms: 1 + 2x + x2 = -4 + 1 Combine like terms: -4 + 1 = -3 1 + 2x + x2 = -3 Factor a perfect square on the left side: (x + 1)(x + 1) = -3 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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